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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/08/2009 : 21:19:38
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I need to buy some quality PRE-WIRED send/return jacks (like those in the upper right corner of a Boss BCB-60). Where can I get a set that I can just drop in and use?
THANKS ALL |
Edited by - DrakeSequation on 03/15/2009 05:37:48 |
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Laurie
Double Platinum Member
    
Canada
4854 Posts |
Posted - 03/10/2009 : 10:10:25
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G'day DrakeSequation!
I'm not actually sure what you are asking for? Whaere do you want to drop the jacks into? What's the actual application? |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/11/2009 : 05:21:19
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Hey Laurie. Thank you for responding.
I have an OC-3 which I like, but don't use very often. It needs to be near the front of my chain (amp < other effects < DS1 < OC3 < CS3 < guitar).
What I'm wanting to do is have two pair of Switchcraft #11 mono in/outs so I can simply patch the OC3 in between the others without physically having to move all the other pedals. It would look like this (< = connected with guitar cable, / = soldered):
DS1 input < SC-B out/in < SC-A out/in < CS3 ouput
With this I could pull the cable connecting SC-A out to SC-B in and put the OC3 there. That would keep it in the correct place in the signal path without it having to sit there all the time. It would look like this:
DS1 input < SC-B out/in < OC3 < SC-A out/in < CS3 ouput
What I really need to know exactly how to wire the jacks to act as just a relay. Is it signal lug to signal lug and ground to ground? That's it?
If you look at my pedalboard (on page 41 or 42) you can see I have done something similar with the B in/out on the BCB-60. I have my tuner connected to B out and mounted on my board. To tune, I plug into B in. |
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Laurie
Double Platinum Member
    
Canada
4854 Posts |
Posted - 03/11/2009 : 06:21:01
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OK... sounds like what you need is a "mono insert point".
Not quite as simple as you might hope. You will need one switchcraft #12A jack or equivalent plus one #11 (not two #11 jacks).
Here is the wiring diagram:

Based on your description, plug the "in" plug into the SC-A output and the "out" plug into the SC-B input.
Plug a patch lead from the "send" jack to the input of the OC-3 and a lead from the output of the OC-3 to the "return" jack when you want the OC-3 in circuit.
Note that with this particular wiring arrangement, if you wanted to, you can "tap off" a send to another pedal chain by plugging a lead only into the "send" jack - with no plug into the "return" jack, the signal into the SC-B input won't be interrupted.
I think this is what you want...? 
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Edited by - Laurie on 03/11/2009 06:34:13 |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/12/2009 : 03:53:41
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I'm not sure I completely understand the wiring diagram you included. I think it may accomplish the same thing but be a bit more efficient? I may want to go into an explanation of that, but before I try to grasp a second wiring scheme, I want to make sure you understand what I am looking for.
I did a mock version (with pics) of what I want using the 4 input/outputs of a BCB-60. This is EXACTLY what I want to do. I would actually use these, except I need them for the end of my signal chain. The singal path is: Return A > Output A > Return B > Output B
Pic of circuit without OC3: http://i456.photobucket.com/albums/qq285/DrakeSequation/DSC05983.jpg
Pic of circuit without OC3 (close-up): http://i456.photobucket.com/albums/qq285/DrakeSequation/DSC05984.jpg
Pic of circuit with OC3 added: http://i456.photobucket.com/albums/qq285/DrakeSequation/DSC05985.jpg
So I am using a cable to connect the output of A to the input of B. I then remove that cable, creating an open (available) input and output to patch the OC3 into.
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Edited by - DrakeSequation on 03/12/2009 03:56:29 |
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Laurie
Double Platinum Member
    
Canada
4854 Posts |
Posted - 03/12/2009 : 07:27:36
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| I'm pretty sure the wiring diagram in the post above will do what you want. It will essentially provide another "output" (what I called "send") and "return". |
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Dr. Bob
Moderator
    
Australia
6593 Posts |
Posted - 03/12/2009 : 12:38:02
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Hi DrakeSequation
Off topic for a bit.
Your clean pics of the BCB-60, now have me GAS-sing for one... 
Regards Dr. Bob  |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/12/2009 : 22:35:52
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Dr. Bob, I'm glad I gave you GAS :). I have more BCB-60 goodness on the way.
Laurie, Why would I use 12b (stereo) jacks with mono plugs? With a 11 and 12b I have five solder points (2 tips, 2 grounds, and 1 sleeve). Will you write in words the solder points in your diagram (12a sleeve to 11 tip, etc.)? Why wouldn't two 11's soldered tip to tip and ground to ground work? I'm trying to understand, so please be patient if I ask stupid or annoying questions. |
Edited by - DrakeSequation on 03/12/2009 22:44:11 |
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Laurie
Double Platinum Member
    
Canada
4854 Posts |
Posted - 03/12/2009 : 23:27:11
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Hey DrakeSequation, you are confusing 12A and 12B (even in your last post). It has to be a 12A (mono, with switch) - if you don't have the switch it will nay work laddie.
Buy two mono plugs. Call one "IN" and one "OUT". Buy a switchcraft #11 jack and call it "SEND" Buy a switchcraft #12A jack and call it "RETURN"
Wire it like this: IN-tip goes to SEND-tip IN-sleeve goes to SEND-sleeve
SEND-tip goes to RETURN-switch (plus has the connection from IN-tip) SEND-sleeve goes to RETURN-sleeve (plus has the connection from IN-sleeve)
RETURN-tip goes to OUT-tip RETURN-sleeve goes to OUT-sleeve (plus has the connection from SEND-sleeve)
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/13/2009 : 00:41:14
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Wiring by numbers. Now you are speaking my language. I get the A/B thing now too.
I want to do this with 4 jacks, just like in the picture demo. No plugs (other than my guitar cable) should be involved.
What brand and/or characteristics should I be looking for in solder? |
Edited by - DrakeSequation on 03/13/2009 00:48:34 |
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nosi0
Gold Member
  
Netherlands
511 Posts |
Posted - 03/13/2009 : 01:49:05
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Laurie's method is actually very smart!

When you don't plug any jack into the send and return jack the signal will go straight from input to output you will not need a "jumper" cable like you have in your picture of the BCB which goes from Return B to Output A.
When you connect your OC-3 to the send and return jacks it disconnects the connection from the input directly through to the output and wires it to the send jack and the return jack then brings the signal to the output jack.
So to use without the OC-3: Plug in to Input take out from Output
TO use with your OC-3: Plug the OC-3 into the send and return jacks.
Hope i make sense! Laurie is a genious.  |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/13/2009 : 05:05:13
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I know the reason I'm not getting what I need because I am asking the question poorly, not because Laurie isn't being helpful. I WANT the jumper cable in there.
So forget the whole OC3 example. What I need to know is this:
How do I wire two mono jacks (presumably #11's) so that the signal carried on the plug placed into the first is transferred out on the plug placed in the second?
With that information I can solve the worlds' problems. |
Edited by - DrakeSequation on 03/13/2009 05:09:15 |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/15/2009 : 05:09:53
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So I got crazy and decided to just do a practical experiment. I wired the jacks like I was first told (and the way that seemed to be most logical) which was:
two SC-11 jacks, wired tip to tip and ground to ground (pictured here): http://i456.photobucket.com/albums/qq285/DrakeSequation/DSC05993.jpg
and it worked (pictures here): http://i456.photobucket.com/albums/qq285/DrakeSequation/DSC05986.jpg
Is there any reason why I shouldn't use this? Remember, all I want to do is transfer the signal coming in on the cable in one jack to go out on the cable in the other. I'm really looking for input (no pun intended, but deeply appreciated). |
Edited by - DrakeSequation on 03/15/2009 05:12:53 |
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nosi0
Gold Member
  
Netherlands
511 Posts |
Posted - 03/15/2009 : 09:49:48
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| Perfect! the less cabling the better though. |
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DrakeSequation
Bronze Member

USA
105 Posts |
Posted - 03/16/2009 : 16:01:47
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Crickets. Crickets.
As the saying goes, �If you want something done right...�. And so I will.
Thank you for your responses. |
Edited by - DrakeSequation on 03/16/2009 16:03:47 |
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Laurie
Double Platinum Member
    
Canada
4854 Posts |
Posted - 03/16/2009 : 17:04:37
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Hi DrakesEquation! Sometimes it can be nearly impossible to communicate through this medium. Even with lots of words and (blurry) pics, it's not possible to really understand what is being asked. On the other hand, if someone comes over to my place and we sit in my workshop and look at it over a beer, it's easy to see what's required and get a solution sorted out.
In response to your comment �As the saying goes, �If you want something done right...�. And so I will�... We did the best we could. For myself, between scratching my head over this, taking the time to create the circuit diagram, and writing the replies, I guess I gave you over an hour of my time. If it didn't get the outcome you were expecting, please accept my apologies, but also please remember - at least I tried.
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